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“Make the Same” – The Secret to Solving Primary Math Questions Efficiently

When solving Math problems involving fractions, ratios, and unit conversions, there’s one simple trick that can help:

πŸ”‘ “Make the Same.”

By aligning denominators, numerators, or total values, we can simplify calculations and avoid mistakes. Let’s go through some examples to see this method in action.


Example 1: Boys and Girls in a School

The ratio of boys to girls in a school is 3:4.
After 3/8 of the girls left, there were 48 more boys than girls.
How many boys were there?

Step 1: Make the Denominators the Same

  • The given ratio is 3:4.
  • The fraction 3/8 tells us that the total number of girls should be divisible by 8.
  • But in the ratio, the number of girls is 4 units, not 8.

To “make the same,” we adjust the ratio so that the number of girls is expressed in eighths.
Since 4 Γ— 2 = 8, we multiply both parts of the ratio by 2 to maintain the same relationship:

  • Boys: 3 Γ— 2 = 6 units
  • Girls: 4 Γ— 2 = 8 units

Now, since 3/8 of the girls left, that means:

  • 3/8 Γ— 8u = 3u girls left.
  • Remaining girls: 8u – 3u = 5u.

Since the boys outnumbered the remaining girls by 48, we set up the equation:

6uβˆ’5u=486u – 5u = 48 1u=481u = 48 6u=6Γ—48=2886u = 6 Γ— 48 = 288

πŸ”Ή There were 288 boys in the school.


Example 2: Decorating Tables and Chairs with Ribbons

7m of ribbon is needed for every 3 tables.
3m of ribbon is needed for every 5 chairs.
Students from Class 6A decorated 30 tables and 30 chairs.
How many more metres of ribbon did they use for tables than for chairs?

Step 1: Make the Number of Tables and Chairs the Same

  • Tables are grouped in 3s, chairs in 5s.
  • LCM of 3 and 5 is 15.
Item Ribbon Usage Equivalent in 15 units
Tables 7m for 3 tables 7 Γ— 5 = 35m for 15 tables
Chairs 3m for 5 chairs 3 Γ— 3 = 9m for 15 chairs

Now, for 30 tables and 30 chairs (twice 15 tables and chairs):

  • Tables: 35m Γ— 2 = 70m
  • Chairs: 9m Γ— 2 = 18m

Difference in ribbon used = 70m – 18m = 52m

πŸ”Ή They used 52m more ribbon for tables than chairs.


Example 3: Shading a Fraction of a Figure

A math problem asking how many more triangles need to be shaded so that 3/4 of a figure made up of 16 similar triangles is shaded. The diagram shows a geometric figure with some triangles already shaded.

The figure is made up of 16 similar triangles.
How many more triangles must be shaded so that 3/4 of the figure is shaded?

Step 1: Make the Denominators the Same

We need 3/4 of the total figure to be shaded.
The figure consists of 16 triangles, but the denominator is 4.

To make them the same, convert 3/4 to a fraction out of 16:

3/4=12/163/4 = 12/16

This means 12 triangles need to be shaded.

Step 2: Find How Many More Need to be Shaded

From the image, we count that 6 triangles are already shaded.

So, the number of additional shaded triangles required is:

12βˆ’6=612 – 6 = 6

πŸ”Ή 6 more triangles must be shaded.


Why “Make the Same” Works Every Time

  • Fractions become whole numbers β†’ Easier to compare.
  • Ratios align with the problem β†’ Prevents miscalculations.
  • Units match up correctly β†’ No confusion in word problems.

Whenever you’re stuck on a Math question, ask yourself:
❓ What do I need to make the same?

This strategy makes problems easier and faster to solve. πŸš€

Would you like more worked examples? Let me know in the comments! 😊

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