When solving Math problems involving fractions, ratios, and unit conversions, thereβs one simple trick that can help:
π “Make the Same.”
By aligning denominators, numerators, or total values, we can simplify calculations and avoid mistakes. Letβs go through some examples to see this method in action.
Example 1: Boys and Girls in a School
The ratio of boys to girls in a school is 3:4.
After 3/8 of the girls left, there were 48 more boys than girls.
How many boys were there?
Step 1: Make the Denominators the Same
- The given ratio is 3:4.
- The fraction 3/8 tells us that the total number of girls should be divisible by 8.
- But in the ratio, the number of girls is 4 units, not 8.
To “make the same,” we adjust the ratio so that the number of girls is expressed in eighths.
Since 4 Γ 2 = 8, we multiply both parts of the ratio by 2 to maintain the same relationship:
- Boys: 3 Γ 2 = 6 units
- Girls: 4 Γ 2 = 8 units
Now, since 3/8 of the girls left, that means:
- 3/8 Γ 8u = 3u girls left.
- Remaining girls: 8u – 3u = 5u.
Since the boys outnumbered the remaining girls by 48, we set up the equation:
6uβ5u=486u – 5u = 486uβ5u=48 1u=481u = 481u=48 6u=6Γ48=2886u = 6 Γ 48 = 2886u=6Γ48=288
πΉ There were 288 boys in the school.
Example 2: Decorating Tables and Chairs with Ribbons
7m of ribbon is needed for every 3 tables.
3m of ribbon is needed for every 5 chairs.
Students from Class 6A decorated 30 tables and 30 chairs.
How many more metres of ribbon did they use for tables than for chairs?
Step 1: Make the Number of Tables and Chairs the Same
- Tables are grouped in 3s, chairs in 5s.
- LCM of 3 and 5 is 15.
Item | Ribbon Usage | Equivalent in 15 units |
---|---|---|
Tables | 7m for 3 tables | 7 Γ 5 = 35m for 15 tables |
Chairs | 3m for 5 chairs | 3 Γ 3 = 9m for 15 chairs |
Now, for 30 tables and 30 chairs (twice 15 tables and chairs):
- Tables: 35m Γ 2 = 70m
- Chairs: 9m Γ 2 = 18m
Difference in ribbon used = 70m – 18m = 52m
πΉ They used 52m more ribbon for tables than chairs.
Example 3: Shading a Fraction of a Figure
The figure is made up of 16 similar triangles.
How many more triangles must be shaded so that 3/4 of the figure is shaded?
Step 1: Make the Denominators the Same
We need 3/4 of the total figure to be shaded.
The figure consists of 16 triangles, but the denominator is 4.
To make them the same, convert 3/4 to a fraction out of 16:
3/4=12/163/4 = 12/163/4=12/16
This means 12 triangles need to be shaded.
Step 2: Find How Many More Need to be Shaded
From the image, we count that 6 triangles are already shaded.
So, the number of additional shaded triangles required is:
12β6=612 – 6 = 612β6=6
πΉ 6 more triangles must be shaded.
Why “Make the Same” Works Every Time
- Fractions become whole numbers β Easier to compare.
- Ratios align with the problem β Prevents miscalculations.
- Units match up correctly β No confusion in word problems.
Whenever you’re stuck on a Math question, ask yourself:
β What do I need to make the same?
This strategy makes problems easier and faster to solve. π
Would you like more worked examples? Let me know in the comments! π